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Script show all the images in a directory

Posted April 27th, 2007 by Mgccl

in

Coding
PHP

View the entire directory's images.
Just a quick script so I can view the entire onion smilies directory
It have no mechanism to filter out anything that is not images, some additional conditions need to be applied.

<?php
	$handle = opendir ('./');
    while (false !== ($file = readdir($handle))) {
        echo '<img src="'.$file.'"/><br />'.$file.'<br />';
    }
?>

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small bug

On Apr/29/2007 10:45:36 Jonathan Street (not verified) says:

You may have noticed already but the first two 'images' don't show up. The first two files are for the current directory and moving up a directory

Something simple like the following should solve this.

<?php
        $handle = opendir ('./');
        while (false !== ($file = readdir($handle))) {
            if($file != "." && $file != ". .") {
                echo '&lt;img src="'.$file.'"/&gt;'.$file.'';
            }
        }
?>

reply

Another improvement

On Apr/30/2007 14:49:33 Mgccl says:

thx :),
Now it will not output the script itself as a image.

<?php
        $handle = opendir ('./');
        while (false !== ($file = readdir($handle))) {
            if($file != "." && $file != ".." && $file != basename(__FILE__)) {
                echo '<img src="'.$file.'"/>'.$file.'';
            }
        }
?>

reply

nice script, thanks. but now

On Oct/10/2008 17:11:53 Charles (not verified) says:

nice script, thanks.

but now can it display the images in order of filename?

reply

Thanks, exactly what I was

On May/02/2008 16:26:56 Anonymous (not verified) says:

Thanks, exactly what I was looking for!

reply

The "Another Improvement" script

On Sep/28/2008 14:24:13 Charles (not verified) says:

I like this one a lot, but have one question...
how can I modify it so it outputs the file name without the period and file type attached?

reply

for this instance, this

On Sep/29/2008 02:27:44 Mgccl says:

for this instance, this should work... did not try the code but I don't think there is an error.
Replaced the instance of $file with substr($file,0,-4). Assuming the the file type has only 3 letters.

<?php
        $handle = opendir ('./');
        while (false !== ($file = readdir($handle))) {
            if($file != "." && $file != ".." && $file != basename(__FILE__)) {
                echo '<img src="'.$file.'"/>'.substr($file,0,-4).'';
            }
        }
?>