Get the file name without the directories

Posted April 30th, 2007 by Mgccl
in

Shocking! This tutorial teaches people very inefficient codes!
Mountains of inefficientness running though every line of the tutorial! AHHHHHhhh
I'm not going to criticize not using __FILE__ part, since sometimes, $_SERVER["SCRIPT_NAME"] can be different from __FILE__.
$file = $_SERVER["SCRIPT_NAME"];
but I have to say something about how to get the a file name without the directories.

$file = $_SERVER["SCRIPT_NAME"];
$break = Explode('/', $file);
$pfile = $break[count($break) - 1];

Build ups of this kind of small unpolished gears could end up with huge performance hit(even though it's usually not noticeable among the users).
I suggest a MUCH faster method:
$pfile = basename(__FILE__);

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